What kind of Database does the PROS CS Software use?
MS Access or SQL. It is selectable.
Does the EWSi System support remote sites?
Yes, the EWSi controllers can be installed on remote location.
Can the PROS CS Software be installed on multiple PCs?
Yes, PROS CS client can be installed on a number of PCs, either local to the server or remotely via the Internet. A USB dongle is required for each client.
Which number of Doors and Users can the EWS system support?
Doors – unlimited; Users – 15000.
Can I trigger a relay or send a mail for any event using the PROS CS software?
Yes, by using the feature “Scenario”.
Which controller besides the EWS can receive Wiegand codes?
The standalone 2 doors controller SC24000, with 4000 users.
What is the capacity of the Fingerprint Readers?
B100 series – 100 fingerprints; BIOC3 series – 9500 fingerprints.
Do you need to enroll the fingerprint on each fingerprint reader in the network?
No. Enrolment is just done once, from any fingerprint reader in the network or from a desktop fingerprint reader.
With the MINI-SA2 Standalone Reader, how can I delete a User that has lost his User Card?
The user card can be deleted with the Shadow Card. The shadow card is specifically designed for that. The Shadow card does not grant access, it is just used for deleting user cards.
In the MINI-SA2 System, Can I register many users under the same shadow card?
Yes, you can add up to 4000 users to the same card. Just note that when deleting a user with the shadow card, all users that are associated to that card will be deleted.
How a magnetic lock is made of?
Primarily of steel, copper and resin.
How to carry out a successful, fault-free installation?
Fitting a magnetic lock is quite simple, and the two illustrations below provide simple explanations on the order of assembly that must be observed.
Common problems and solutions
The armature plate is too tight.
This is a classic error in the first installations. The fitter is concerned that the
armature plate may come loose and tightens the screw to the point of crushing
the rubber washers and locking up the assembly. The door has an angular
movement that can only be offset at the end of its travel with the flexibility of the
armature plate. The more flexible the armature plate is, the better the system works.
The voltage at the terminals of the lock is too weak:
This is another classic case of fitters starting out on lock fitting. The magnetic
locks must be supplied with power of at least 12V DC or 24V DC. If this voltage
is lower at the terminals of the lock, the pulling force will be weaker and the
signalling will not work correctly. Attention: The locks are delivered from the
factory configured at 24V DC. If you use a 12V DC power supply, consider
changing the choice of voltage.
Holding force reduced.
Possible cause: Bad physical contact between armature plate and magnet
surface. Solutions: Make sure than surface contact is cleaned and well aligned
with the armature plate.
There is a delay in door release when power off.
Possible cause: The power switch-off is disturbed by the power supply
stabilization. Solution: The power cut must be done between the PSU and lock.
Not at the AC input of the PSU.
How to clean the electromagnet lock?
The electromagnets do not require special maintenance. It is important not to clean them with an abrasive or a solvent.
Electrical connections. How to make sure they work correctly.
Connecting a magnetic lock is child’s play. However, it is a good idea to carefully read the electrical concepts below:
The basic formula:
Rc: Resistance of the cable
?: Specific resistance determined by the cable type. (For copper, 0.0175 ohms)
L: Length in metres (Attention: there are 2 wires, so do not forget to multiply by two)
S: Section of the cable in mm²
And Ohm´s law:
R: Resistance (ohms)
U: Voltage (volts)
I : Current (amperes)
Three magnetic locks are fitted 25 metres from the power supply. They are supplied at 12 VDC and consume 500 mA each. The cable has a section of 0.5 mm².
We therefore have a cable length of 50 m (there are two wires) and overall consumption of 1.5 A (1,500 mA).
A) Calculation of the cable resistance:
R = (0,0175 x 50) / 0,5 = 1,75 ohm
B) Calculation of the voltage drop:
U = 1,75 x 1.5 = 2.62 volts
A lock must have at least its nominal voltage at its terminals. In this case, 12 VDC. Since we know that the cable voltage will fall by 2.62 volts, we must adjust the power to at least 14.62 volts. Or preferably, use a cable with a greater section.
Two cases may cause poor operation: